# How do you solve #5/(x^3-x^2-4X+4) < 0#?

##### 1 Answer

Oct 9, 2015

This reduces to finding out when

#### Explanation:

so let's find where that happens...

Let

We can factor

#f(x) = x^3-x^2-4x+4#

#= (x^3-x^2)-(4x-4)#

#= x^2(x-1) - 4(x-1)#

#= (x^2-4)(x-1)#

#= (x-2)(x+2)(x-1)#

The graph of

Since the coefficient of

graph{x^3-x^2-4x+4 [-9.92, 10.08, -3.12, 6.88]}

graph{5/(x^3-x^2-4x+4) [-18.6, 17.45, -10.69, 7.33]}